25kw380v用多少平方的电线
1.16 mm2 电缆足以满足 25 kW 380 V 电源 2. 电流计算公式为 I=P/U，其中 I 代表电流（安培），P 代表功率（千瓦），U 代表电压（。伏）。
3、在380伏电压下，25千瓦功率对应的电流约为I=25kW/380V≈65.8A，即约65.8安培。
4、为确保安全，建议使用16平方毫米电缆。
5、如果电源线距离较长，建议改用25平方毫米铜芯导体。
1/4平方毫米的铜芯线正常情况下能承载的最大电流在6～10A之间。
7、该公式表明，当电压恒定时，功率与电流成正比：当电压固定，功率增大，电流也增大，功率减小，电流也相应减小；
380v25kw用多少平方的线
20mm²线。使用25 kW 380 V设备，操作电流约为50安培。
根据电线安全电力路由的标准，电线通常必须能够导致其标称电流的两倍。
因此，一个重50个设备需要具有标称功率为100安培的电缆。
根据标准，10到50平方米的铜线肯定可以每平方毫米磨损5安培。
为了覆盖100安培的电力需求，应使用20平方毫米铜线。
380V25千瓦多大电缆
1、首先要计算25kW负载线的电流。如果是对称三相25kW，电流为44.74A，则表查需要10平方铜芯线，其截流电流为59A。
2、三相电源电路计算公式：P=1.732iucos φ。
由三相电路功率公式，可以得出线电流公式：i = p/1.732ucos φ； 功率因数。
25kw380v需要多大线
选择16平方铜芯线时，应考虑其在380V三相电气系统中的载流量。对于阻性负载，铜芯线可承受约32KW的功率，对于感性负载，其承受能力约为25KW。
考虑60KW负载时，电流约为114A，因此建议选择不小于35平方毫米的铜导体面积，以确保安全。
同时建议使用250A的空气开关，以保证电路安全。
在100米三相四线16平方铜芯线的应用场景下，理论上可承载40千瓦的负载。
但需要注意的是，当电线长度达到100米时，运行时的电压降应保持在正常范围内，通常不超过9V。
在220V电压下，16平方铜芯线的安全载流量为91A，最大负载20KW。
该参数保证了线材在长期使用过程中不会过热，从而避免线材烧毁、线材老化等安全隐患。
在对称三相电力系统中，16平方铜芯线的截流容量约为83A，单相电下可承受约18.3千瓦，三相电下约46.4千瓦。
在220V民用系统中，16平方米的铜芯线最大负载也为20KW，是场所内长期稳定的运行负载，保证用电安全。
在380V系统中，16平方米铜芯线的最大载流量为94A左右，考虑到实际使用中的安全系数，建议在75A左右。
这意味着在220V电压下，电线可以安全承载约220.5KW的负载。
综上所述，16平方铜芯线的载流量在不同电压和负载条件下有所不同，但总的来说，在满足安全标准的情况下，可以满足各种功率要求。
在实际应用中，应根据具体的使用条件和安全标准选择合适的电线规格。
380v,25KW功率。 用多少平米的线合适？
380V和25kW电源系统的适当电线尺寸取决于当前尺寸。取决于当前的电源和电压。
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实际操作，实际操作。
中学可能低于此价值。
根据国家电力条款，应选择电线，以确保与当前数据量相比，安全和电线的寿命大量。
通常，铜线高于铝线。
通过考虑将来增加负载，我们可以选择当前情况90a的电线。
The common requirements in the copper guide line is 6 squaremmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm (mm. 因此，6平方mm的680V负载和25kW载荷中的铜毫米应足够。
请。
其他，在实际安装和环境之前，电线的长度，长度和电线的长度，温度，建议与专业工程师或技术人员进行咨询。
